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Generic type parameters cannot be primitive types in Java. Fixed!

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This commit is contained in:
the_fiddler 2011-12-05 13:28:17 +00:00
parent e643d97317
commit 9848b51089
1 changed files with 7 additions and 4 deletions
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11
Source/Bind/JavaSpecWriter.cs
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@ -162,7 +162,7 @@ namespace Bind
static void WriteWrapper(Function f, BindStreamWriter sw) static void WriteWrapper(Function f, BindStreamWriter sw)
{ {
var valid = true; var valid = true;
var generic_parameters = GenerateGenericParameterString(f); var generic_parameters = GenerateGenericTypeString(f);
var parameters = GenerateParameterString(f, out valid); var parameters = GenerateParameterString(f, out valid);
if (!valid) if (!valid)
return; return;
@ -211,7 +211,10 @@ namespace Bind
else else
sb.Append("Ref<"); sb.Append("Ref<");
sb.Append(p.CurrentType); // Hack: primitive types cannot be used as type parameters in Java.
// Ensure the first letter is upper-case in order to use the boxed versions
// of primitive types (i.e. "Byte" rather than "byte" etc).
sb.Append(Char.ToUpper(p.CurrentType[0]) + p.CurrentType.Substring(1));
sb.Append(">"); sb.Append(">");
} }
else if (p.Pointer > 0 && p.Array > 0) else if (p.Pointer > 0 && p.Array > 0)
@ -246,9 +249,9 @@ namespace Bind
#endregion #endregion
#region GenerateGenericParameterString #region GenerateGenericTypeString
static string GenerateGenericParameterString(Function f) static string GenerateGenericTypeString(Function f)
{ {
var parameters = f.Parameters.Where(p => p.Generic); var parameters = f.Parameters.Where(p => p.Generic);
if (parameters.Count() > 0) if (parameters.Count() > 0)