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Correct some statements about the ordering of A and B
Signed-off-by: Gilles Peskine <Gilles.Peskine@arm.com>
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@ -2428,12 +2428,15 @@ int mbedtls_mpi_gcd( mbedtls_mpi *G, const mbedtls_mpi *A, const mbedtls_mpi *B
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* minor differences:
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* - Sequences of multiplications or divisions by 2 are grouped into a
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* single shift operation.
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* - The procedure in HAC assumes that 0 < A <= B.
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* - The condition A <= B is not actually necessary for correctness;
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* the first round through the loop results in TA < TB.
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* - If A = 0, the loop goes through 0 iterations and the result is
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* correctly B.
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* - The case B=0 was short-circuited above.
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* - The procedure in HAC assumes that 0 < TB <= TA.
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* - The condition TB <= TA is not actually necessary for correctness.
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* TA and TB have symmetric roles except for the loop termination
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* condition, and the shifts at the beginning of the loop body
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* remove any significance from the ordering of TA vs TB before
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* the shifts.
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* - If TA = 0, the loop goes through 0 iterations and the result is
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* correctly TB.
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* - The case TB = 0 was short-circuited above.
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*
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* For the correctness proof below, decompose the original values of
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* A and B as
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