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Change ASSERT_ALLOC to take a size in elements, not bytes

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`ASSERT_ALLOC(p, length)` now allocates `length` elements, i.e.
`length * sizeof(*p)` bytes.
This commit is contained in:
Gilles Peskine 2018-11-30 18:51:45 +01:00
parent 69f976b1d6
commit 7f6e3a868a
1 changed files with 13 additions and 12 deletions
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11
tests/suites/helpers.function
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@ -95,7 +95,7 @@ typedef struct data_tag
* You must set \p pointer to \c NULL before calling this macro and
* put `mbedtls_free( pointer )` in the test's cleanup code.
*
* If \p size is zero, the resulting \p pointer will be \c NULL.
* If \p length is zero, the resulting \p pointer will be \c NULL.
* This is usually what we want in tests since API functions are
* supposed to accept null pointers when a buffer size is zero.
*
@ -105,17 +105,18 @@ typedef struct data_tag
* \param pointer An lvalue where the address of the allocated buffer
* will be stored.
* This expression may be evaluated multiple times.
* \param size Buffer size to allocate in bytes.
* \param length Number of elements to allocate.
* This expression may be evaluated multiple times.
*
*/
#define ASSERT_ALLOC( pointer, size ) \
#define ASSERT_ALLOC( pointer, length ) \
do \
{ \
TEST_ASSERT( ( pointer ) == NULL ); \
if( ( size ) != 0 ) \
if( ( length ) != 0 ) \
{ \
( pointer ) = mbedtls_calloc( 1, ( size ) ); \
( pointer ) = mbedtls_calloc( sizeof( *( pointer ) ), \
( length ) ); \
TEST_ASSERT( ( pointer ) != NULL ); \
} \
} \