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softfloat: do not set denominator high bit for floatx80 remainder

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The floatx80 remainder implementation unnecessarily sets the high bit
of bSig explicitly. By that point in the function, arguments that are
invalid, zero, infinity or NaN have already been handled and
subnormals have been through normalizeFloatx80Subnormal, so the high
bit will already be set. Remove the unnecessary code.

Backports commit 566601f1f9d972e44214696d3cb320e6c18880aa from qemu
This commit is contained in:
Joseph Myers 2021-02-25 13:37:12 -05:00 committed by Lioncash
parent 2d50384633
commit e4cfbc1f06
1 changed files with 0 additions and 1 deletions
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qemu/fpu/softfloat.c
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@ -5713,7 +5713,6 @@ floatx80 floatx80_modrem(floatx80 a, floatx80 b, bool mod,
if ( aSig0 == 0 ) return a;
normalizeFloatx80Subnormal( aSig0, &aExp, &aSig0 );
}
bSig |= UINT64_C(0x8000000000000000);
zSign = aSign;
expDiff = aExp - bExp;
aSig1 = 0;